Base | Representation |
---|---|
bin | 100100100101001000010… |
… | …111111110100001100001 |
3 | 22220022110221221210021021 |
4 | 210211020113332201201 |
5 | 312141200122104441 |
6 | 5202450545325441 |
7 | 346420365261001 |
oct | 44451027764141 |
9 | 8808427853237 |
10 | 2513770113121 |
11 | 88a0a1771063 |
12 | 347228636881 |
13 | 1530804a1377 |
14 | 8994a828001 |
15 | 455c79843d1 |
hex | 249485fe861 |
2513770113121 has 8 divisors (see below), whose sum is σ = 2533167302400. Its totient is φ = 2494447386000.
The previous prime is 2513770113031. The next prime is 2513770113187. The reversal of 2513770113121 is 1213110773152.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2513770113121 - 213 = 2513770104929 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2513770119121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18547761 + ... + 18682798.
It is an arithmetic number, because the mean of its divisors is an integer number (316645912800).
Almost surely, 22513770113121 is an apocalyptic number.
It is an amenable number.
2513770113121 is a deficient number, since it is larger than the sum of its proper divisors (19397189279).
2513770113121 is a wasteful number, since it uses less digits than its factorization.
2513770113121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 37231079.
The product of its (nonzero) digits is 8820, while the sum is 34.
Adding to 2513770113121 its reverse (1213110773152), we get a palindrome (3726880886273).
The spelling of 2513770113121 in words is "two trillion, five hundred thirteen billion, seven hundred seventy million, one hundred thirteen thousand, one hundred twenty-one".
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