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2513890242211 is a prime number
BaseRepresentation
bin100100100101001111100…
…010001110111010100011
322220022210022222222101211
4210211033202032322203
5312141421400222321
65202510520210551
7346423354330405
oct44451742167243
98808708888354
102513890242211
1188a1535608a7
12347260909a57
1315309c341c7a
148995c778b75
15455d32b30e1
hex2494f88eea3

2513890242211 has 2 divisors, whose sum is σ = 2513890242212. Its totient is φ = 2513890242210.

The previous prime is 2513890242121. The next prime is 2513890242271. The reversal of 2513890242211 is 1122420983152.

2513890242211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (2513890242121) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2513890242211 - 213 = 2513890234019 is a prime.

It is not a weakly prime, because it can be changed into another prime (2513890242271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256945121105 + 1256945121106.

It is an arithmetic number, because the mean of its divisors is an integer number (1256945121106).

Almost surely, 22513890242211 is an apocalyptic number.

2513890242211 is a deficient number, since it is larger than the sum of its proper divisors (1).

2513890242211 is an equidigital number, since it uses as much as digits as its factorization.

2513890242211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 40.

The spelling of 2513890242211 in words is "two trillion, five hundred thirteen billion, eight hundred ninety million, two hundred forty-two thousand, two hundred eleven".