Base | Representation |
---|---|
bin | 10111011010011110… |
… | …110110001111110011 |
3 | 2101220002000102011101 |
4 | 113122132312033303 |
5 | 402441412343313 |
6 | 15314353025231 |
7 | 1550000333533 |
oct | 273236661763 |
9 | 71802012141 |
10 | 25140356083 |
11 | a731091697 |
12 | 4a57555217 |
13 | 24a863995b |
14 | 1306c814c3 |
15 | 9c21995dd |
hex | 5da7b63f3 |
25140356083 has 2 divisors, whose sum is σ = 25140356084. Its totient is φ = 25140356082.
The previous prime is 25140355969. The next prime is 25140356173. The reversal of 25140356083 is 38065304152.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25140356083 - 225 = 25106801651 is a prime.
It is not a weakly prime, because it can be changed into another prime (25140356183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12570178041 + 12570178042.
It is an arithmetic number, because the mean of its divisors is an integer number (12570178042).
Almost surely, 225140356083 is an apocalyptic number.
25140356083 is a deficient number, since it is larger than the sum of its proper divisors (1).
25140356083 is an equidigital number, since it uses as much as digits as its factorization.
25140356083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 37.
The spelling of 25140356083 in words is "twenty-five billion, one hundred forty million, three hundred fifty-six thousand, eighty-three".
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