Base | Representation |
---|---|
bin | 100100100101100011111… |
… | …011111001001001101001 |
3 | 22220100200012001010211111 |
4 | 210211203323321021221 |
5 | 312143122010410004 |
6 | 5203004504230321 |
7 | 346435011513661 |
oct | 44454373711151 |
9 | 8810605033744 |
10 | 2514232513129 |
11 | 88a309787027 |
12 | 34733746b3a1 |
13 | 15312522013c |
14 | 89991dd31a1 |
15 | 45603371a04 |
hex | 24963ef9269 |
2514232513129 has 2 divisors, whose sum is σ = 2514232513130. Its totient is φ = 2514232513128.
The previous prime is 2514232513103. The next prime is 2514232513141. The reversal of 2514232513129 is 9213152324152.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2307345810025 + 206886703104 = 1518995^2 + 454848^2 .
It is a cyclic number.
It is not a de Polignac number, because 2514232513129 - 213 = 2514232504937 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2514232513091 and 2514232513100.
It is not a weakly prime, because it can be changed into another prime (2514232513159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1257116256564 + 1257116256565.
It is an arithmetic number, because the mean of its divisors is an integer number (1257116256565).
Almost surely, 22514232513129 is an apocalyptic number.
It is an amenable number.
2514232513129 is a deficient number, since it is larger than the sum of its proper divisors (1).
2514232513129 is an equidigital number, since it uses as much as digits as its factorization.
2514232513129 is an evil number, because the sum of its binary digits is even.
The product of its digits is 129600, while the sum is 40.
The spelling of 2514232513129 in words is "two trillion, five hundred fourteen billion, two hundred thirty-two million, five hundred thirteen thousand, one hundred twenty-nine".
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