Base | Representation |
---|---|
bin | 10111011010101100… |
… | …111010101001010001 |
3 | 2101220022221210012002 |
4 | 113122230322221101 |
5 | 402443333402423 |
6 | 15315004043345 |
7 | 1550043564026 |
oct | 273254725121 |
9 | 71808853162 |
10 | 25144044113 |
11 | a733180551 |
12 | 4a58833555 |
13 | 24a932b516 |
14 | 130756154d |
15 | 9c2677228 |
hex | 5dab3aa51 |
25144044113 has 2 divisors, whose sum is σ = 25144044114. Its totient is φ = 25144044112.
The previous prime is 25144044109. The next prime is 25144044119. The reversal of 25144044113 is 31144044152.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24475976704 + 668067409 = 156448^2 + 25847^2 .
It is a cyclic number.
It is not a de Polignac number, because 25144044113 - 22 = 25144044109 is a prime.
It is not a weakly prime, because it can be changed into another prime (25144044119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12572022056 + 12572022057.
It is an arithmetic number, because the mean of its divisors is an integer number (12572022057).
Almost surely, 225144044113 is an apocalyptic number.
It is an amenable number.
25144044113 is a deficient number, since it is larger than the sum of its proper divisors (1).
25144044113 is an equidigital number, since it uses as much as digits as its factorization.
25144044113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 25144044113 its reverse (31144044152), we get a palindrome (56288088265).
The spelling of 25144044113 in words is "twenty-five billion, one hundred forty-four million, forty-four thousand, one hundred thirteen".
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