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2519655690241 is a prime number
BaseRepresentation
bin100100101010100111001…
…011101011000000000001
322220212200010201002021001
4210222213023223000001
5312240223324041431
65205302553532001
7350016262663654
oct44524713530001
98825603632231
102519655690241
11891641a4a288
123483ab714001
131537aa946891
1489d4836d89b
154581e518e61
hex24aa72eb001

2519655690241 has 2 divisors, whose sum is σ = 2519655690242. Its totient is φ = 2519655690240.

The previous prime is 2519655690199. The next prime is 2519655690263. The reversal of 2519655690241 is 1420965569152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1981492599025 + 538163091216 = 1407655^2 + 733596^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2519655690241 is a prime.

It is not a weakly prime, because it can be changed into another prime (2519655690341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1259827845120 + 1259827845121.

It is an arithmetic number, because the mean of its divisors is an integer number (1259827845121).

Almost surely, 22519655690241 is an apocalyptic number.

It is an amenable number.

2519655690241 is a deficient number, since it is larger than the sum of its proper divisors (1).

2519655690241 is an equidigital number, since it uses as much as digits as its factorization.

2519655690241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832000, while the sum is 55.

The spelling of 2519655690241 in words is "two trillion, five hundred nineteen billion, six hundred fifty-five million, six hundred ninety thousand, two hundred forty-one".