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252004414117 = 272399251603
BaseRepresentation
bin1110101010110010100…
…0100011001010100101
3220002110121202122101011
43222230220203022211
513112101112222432
6311434053102221
724130622114461
oct3525450431245
9802417678334
10252004414117
1197968a16245
1240a0b927971
131a9c1420451
14c2a8ad94a1
15684dc9e847
hex3aaca232a5

252004414117 has 4 divisors (see below), whose sum is σ = 252013692960. Its totient is φ = 251995135276.

The previous prime is 252004414099. The next prime is 252004414141. The reversal of 252004414117 is 711414400252.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-252004414117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252004414217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4598563 + ... + 4653040.

It is an arithmetic number, because the mean of its divisors is an integer number (63003423240).

Almost surely, 2252004414117 is an apocalyptic number.

It is an amenable number.

252004414117 is a deficient number, since it is larger than the sum of its proper divisors (9278843).

252004414117 is an equidigital number, since it uses as much as digits as its factorization.

252004414117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9278842.

The product of its (nonzero) digits is 8960, while the sum is 31.

Adding to 252004414117 its reverse (711414400252), we get a palindrome (963418814369).

The spelling of 252004414117 in words is "two hundred fifty-two billion, four million, four hundred fourteen thousand, one hundred seventeen".

Divisors: 1 27239 9251603 252004414117