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252010404013253 = 1238212035279993
BaseRepresentation
bin111001010011001110111110…
…100111000110010011000101
31020001021221220100121210210112
4321103032332213012103011
5231012414301411411003
62251551551550002405
7104040102512144114
oct7123167647062305
91201257810553715
10252010404013253
1173331015193386
122432137a4a6405
13aa8062c84b882
14463352376bc7b
151e205802923d8
hexe533be9c64c5

252010404013253 has 4 divisors (see below), whose sum is σ = 252012439417068. Its totient is φ = 252008368609440.

The previous prime is 252010404013217. The next prime is 252010404013271. The reversal of 252010404013253 is 352310404010252.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8848857938209 + 243161546075044 = 2974703^2 + 15593638^2 .

It is a cyclic number.

It is not a de Polignac number, because 252010404013253 - 210 = 252010404012229 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252010404013553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1017516176 + ... + 1017763817.

It is an arithmetic number, because the mean of its divisors is an integer number (63003109854267).

Almost surely, 2252010404013253 is an apocalyptic number.

It is an amenable number.

252010404013253 is a deficient number, since it is larger than the sum of its proper divisors (2035403815).

252010404013253 is a wasteful number, since it uses less digits than its factorization.

252010404013253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2035403814.

The product of its (nonzero) digits is 28800, while the sum is 32.

The spelling of 252010404013253 in words is "two hundred fifty-two trillion, ten billion, four hundred four million, thirteen thousand, two hundred fifty-three".

Divisors: 1 123821 2035279993 252010404013253