2520134031 has 8 divisors (see below), whose sum is σ = 3431672064. Its totient is φ = 1644342680.

The previous prime is 2520133997. The next prime is 2520134039. The reversal of 2520134031 is 1304310252.

2520134031 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2520134031 - 2¹⁷ = 2520002959 is a prime.

It is a super-2 number, since 2×2520134031² = 12702151068408617922, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2520133989 and 2520134007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2520134039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8936505 + ... + 8936786.

It is an arithmetic number, because the mean of its divisors is an integer number (428959008).

Almost surely, 2^2520134031 is an apocalyptic number.

2520134031 is a deficient number, since it is larger than the sum of its proper divisors (911538033).

2520134031 is a wasteful number, since it uses less digits than its factorization.

2520134031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17873341.

The product of its (nonzero) digits is 720, while the sum is 21.

The square root of 2520134031 is about 50200.9365550086. The cubic root of 2520134031 is about 1360.8425486696.

Adding to 2520134031 its reverse (1304310252), we get a palindrome (3824444283).

The spelling of 2520134031 in words is "two billion, five hundred twenty million, one hundred thirty-four thousand, thirty-one".