Base | Representation |
---|---|
bin | 1001011000110110… |
… | …0011001000111011 |
3 | 20111122002002012211 |
4 | 2112031203020323 |
5 | 20130123243303 |
6 | 1054023115551 |
7 | 116310534016 |
oct | 22615431073 |
9 | 6448062184 |
10 | 2520134203 |
11 | 1083606144 |
12 | 5a3ba2bb7 |
13 | 31215b992 |
14 | 19c9b237d |
15 | eb3a666d |
hex | 9636323b |
2520134203 has 2 divisors, whose sum is σ = 2520134204. Its totient is φ = 2520134202.
The previous prime is 2520134171. The next prime is 2520134263. The reversal of 2520134203 is 3024310252.
2520134203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2520134203 - 25 = 2520134171 is a prime.
It is a super-2 number, since 2×25201342032 = 12702152802260890418, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2520134263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1260067101 + 1260067102.
It is an arithmetic number, because the mean of its divisors is an integer number (1260067102).
Almost surely, 22520134203 is an apocalyptic number.
2520134203 is a deficient number, since it is larger than the sum of its proper divisors (1).
2520134203 is an equidigital number, since it uses as much as digits as its factorization.
2520134203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 22.
The square root of 2520134203 is about 50200.9382681240. The cubic root of 2520134203 is about 1360.8425796289.
Adding to 2520134203 its reverse (3024310252), we get a palindrome (5544444455).
The spelling of 2520134203 in words is "two billion, five hundred twenty million, one hundred thirty-four thousand, two hundred three".
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