Base | Representation |
---|---|
bin | 100100101011001001101… |
… | …110110100111101001001 |
3 | 22220221011112101220110011 |
4 | 210223021232310331021 |
5 | 312242420221101101 |
6 | 5205440301351521 |
7 | 350036531600614 |
oct | 44531156647511 |
9 | 8827145356404 |
10 | 2520235331401 |
11 | 89190a162267 |
12 | 3485318685a1 |
13 | 153870a64908 |
14 | 89da133717b |
15 | 45855364751 |
hex | 24ac9bb4f49 |
2520235331401 has 2 divisors, whose sum is σ = 2520235331402. Its totient is φ = 2520235331400.
The previous prime is 2520235331377. The next prime is 2520235331437. The reversal of 2520235331401 is 1041335320252.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1747988073225 + 772247258176 = 1322115^2 + 878776^2 .
It is a cyclic number.
It is not a de Polignac number, because 2520235331401 - 213 = 2520235323209 is a prime.
It is a super-2 number, since 2×25202353314012 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2520235331701) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1260117665700 + 1260117665701.
It is an arithmetic number, because the mean of its divisors is an integer number (1260117665701).
Almost surely, 22520235331401 is an apocalyptic number.
It is an amenable number.
2520235331401 is a deficient number, since it is larger than the sum of its proper divisors (1).
2520235331401 is an equidigital number, since it uses as much as digits as its factorization.
2520235331401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 31.
The spelling of 2520235331401 in words is "two trillion, five hundred twenty billion, two hundred thirty-five million, three hundred thirty-one thousand, four hundred one".
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