Base | Representation |
---|---|
bin | 11110000010110… |
… | …11110001100011 |
3 | 122120020122212001 |
4 | 33001123301203 |
5 | 1004010043042 |
6 | 41001544431 |
7 | 6150153301 |
oct | 1701336143 |
9 | 576218761 |
10 | 252034147 |
11 | 11a2a2a92 |
12 | 704a5117 |
13 | 402a5541 |
14 | 25689271 |
15 | 171d6bb7 |
hex | f05bc63 |
252034147 has 2 divisors, whose sum is σ = 252034148. Its totient is φ = 252034146.
The previous prime is 252034067. The next prime is 252034169. The reversal of 252034147 is 741430252.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 252034147 - 27 = 252034019 is a prime.
It is a super-2 number, since 2×2520341472 = 127042422508035218, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (252034747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126017073 + 126017074.
It is an arithmetic number, because the mean of its divisors is an integer number (126017074).
Almost surely, 2252034147 is an apocalyptic number.
252034147 is a deficient number, since it is larger than the sum of its proper divisors (1).
252034147 is an equidigital number, since it uses as much as digits as its factorization.
252034147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 28.
The square root of 252034147 is about 15875.5833593604. The cubic root of 252034147 is about 631.6644882035.
Adding to 252034147 its reverse (741430252), we get a palindrome (993464399).
The spelling of 252034147 in words is "two hundred fifty-two million, thirty-four thousand, one hundred forty-seven".
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