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252099445249 is a prime number
BaseRepresentation
bin1110101011001001001…
…1000100001000000001
3220002201020120201120201
43222302103010020001
513112244424221444
6311451330005201
724133154633251
oct3526223041001
9802636521521
10252099445249
1197a07623573
1240a37716801
131aa080143a2
14c2b7595961
1568572c1dd4
hex3ab24c4201

252099445249 has 2 divisors, whose sum is σ = 252099445250. Its totient is φ = 252099445248.

The previous prime is 252099445219. The next prime is 252099445343. The reversal of 252099445249 is 942544990252.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 224694960400 + 27404484849 = 474020^2 + 165543^2 .

It is a cyclic number.

It is not a de Polignac number, because 252099445249 - 27 = 252099445121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 252099445249.

It is not a weakly prime, because it can be changed into another prime (252099445219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126049722624 + 126049722625.

It is an arithmetic number, because the mean of its divisors is an integer number (126049722625).

Almost surely, 2252099445249 is an apocalyptic number.

It is an amenable number.

252099445249 is a deficient number, since it is larger than the sum of its proper divisors (1).

252099445249 is an equidigital number, since it uses as much as digits as its factorization.

252099445249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9331200, while the sum is 55.

The spelling of 252099445249 in words is "two hundred fifty-two billion, ninety-nine million, four hundred forty-five thousand, two hundred forty-nine".