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25213142531 is a prime number
BaseRepresentation
bin10111011110110100…
…100000011000000011
32102002010222100101202
4113132310200120003
5403114031030111
615325513051415
71551543114113
oct273664403003
972063870352
1025213142531
11a769186185
124a779b6b6b
1324ba742865
1413127cb043
159c8775b3b
hex5ded20603

25213142531 has 2 divisors, whose sum is σ = 25213142532. Its totient is φ = 25213142530.

The previous prime is 25213142489. The next prime is 25213142551. The reversal of 25213142531 is 13524131252.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25213142531 - 230 = 24139400707 is a prime.

It is a super-2 number, since 2×252131425312 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25213142494 and 25213142503.

It is not a weakly prime, because it can be changed into another prime (25213142551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12606571265 + 12606571266.

It is an arithmetic number, because the mean of its divisors is an integer number (12606571266).

Almost surely, 225213142531 is an apocalyptic number.

25213142531 is a deficient number, since it is larger than the sum of its proper divisors (1).

25213142531 is an equidigital number, since it uses as much as digits as its factorization.

25213142531 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7200, while the sum is 29.

Adding to 25213142531 its reverse (13524131252), we get a palindrome (38737273783).

The spelling of 25213142531 in words is "twenty-five billion, two hundred thirteen million, one hundred forty-two thousand, five hundred thirty-one".