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25231254113353 is a prime number
BaseRepresentation
bin1011011110010100110111…
…11100000100110001001001
310022100002021110222210001011
411233022123330010301021
511301342102023111403
6125355024512523521
75212616666224051
oct557123374046111
9108302243883034
1025231254113353
118048573195742
1229b5b9bb505a1
1311103b281c162
146332b0908561
152db4c97cea6d
hex16f29bf04c49

25231254113353 has 2 divisors, whose sum is σ = 25231254113354. Its totient is φ = 25231254113352.

The previous prime is 25231254113309. The next prime is 25231254113437. The reversal of 25231254113353 is 35331145213252.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19445559922944 + 5785694190409 = 4409712^2 + 2405347^2 .

It is a cyclic number.

It is not a de Polignac number, because 25231254113353 - 217 = 25231253982281 is a prime.

It is not a weakly prime, because it can be changed into another prime (25231254113953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12615627056676 + 12615627056677.

It is an arithmetic number, because the mean of its divisors is an integer number (12615627056677).

Almost surely, 225231254113353 is an apocalyptic number.

It is an amenable number.

25231254113353 is a deficient number, since it is larger than the sum of its proper divisors (1).

25231254113353 is an equidigital number, since it uses as much as digits as its factorization.

25231254113353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 324000, while the sum is 40.

The spelling of 25231254113353 in words is "twenty-five trillion, two hundred thirty-one billion, two hundred fifty-four million, one hundred thirteen thousand, three hundred fifty-three".