Base | Representation |
---|---|
bin | 1001011001101000… |
… | …0011111100011111 |
3 | 20111212020201200000 |
4 | 2112122003330133 |
5 | 20131443224203 |
6 | 1054221305343 |
7 | 116350445004 |
oct | 22632037437 |
9 | 6455221600 |
10 | 2523414303 |
11 | 1085446573 |
12 | 5a5105253 |
13 | 312a39977 |
14 | 19d1c78ab |
15 | eb8034a3 |
hex | 96683f1f |
2523414303 has 24 divisors (see below), whose sum is σ = 3805017216. Its totient is φ = 1671111000.
The previous prime is 2523414281. The next prime is 2523414317. The reversal of 2523414303 is 3034143252.
It is not a de Polignac number, because 2523414303 - 29 = 2523413791 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an alternating number because its digits alternate between even and odd.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2523414343) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2308 + ... + 71078.
It is an arithmetic number, because the mean of its divisors is an integer number (158542384).
Almost surely, 22523414303 is an apocalyptic number.
2523414303 is a deficient number, since it is larger than the sum of its proper divisors (1281602913).
2523414303 is an equidigital number, since it uses as much as digits as its factorization.
2523414303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68937 (or 68925 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 27.
The square root of 2523414303 is about 50233.5973527678. The cubic root of 2523414303 is about 1361.4327286974.
Adding to 2523414303 its reverse (3034143252), we get a palindrome (5557557555).
The spelling of 2523414303 in words is "two billion, five hundred twenty-three million, four hundred fourteen thousand, three hundred three".
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