Base | Representation |
---|---|
bin | 1110101100110100100… |
… | …1111001101011011001 |
3 | 220010212122102200220111 |
4 | 3223031021321223121 |
5 | 13114210301343433 |
6 | 312004143324321 |
7 | 24150265550464 |
oct | 3531511715331 |
9 | 803778380814 |
10 | 252550027993 |
11 | 981189a7aaa |
12 | 40b425b06a1 |
13 | 1aa7a4863b3 |
14 | c31b3662db |
15 | 6881b27dcd |
hex | 3acd279ad9 |
252550027993 has 2 divisors, whose sum is σ = 252550027994. Its totient is φ = 252550027992.
The previous prime is 252550027913. The next prime is 252550028011. The reversal of 252550027993 is 399720055252.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 239226635664 + 13323392329 = 489108^2 + 115427^2 .
It is a cyclic number.
It is not a de Polignac number, because 252550027993 - 213 = 252550019801 is a prime.
It is not a weakly prime, because it can be changed into another prime (252550027913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126275013996 + 126275013997.
It is an arithmetic number, because the mean of its divisors is an integer number (126275013997).
Almost surely, 2252550027993 is an apocalyptic number.
It is an amenable number.
252550027993 is a deficient number, since it is larger than the sum of its proper divisors (1).
252550027993 is an equidigital number, since it uses as much as digits as its factorization.
252550027993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1701000, while the sum is 49.
The spelling of 252550027993 in words is "two hundred fifty-two billion, five hundred fifty million, twenty-seven thousand, nine hundred ninety-three".
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