Base | Representation |
---|---|
bin | 10111100001011010… |
… | …001001100100110001 |
3 | 2102012011200102212212 |
4 | 113201122021210301 |
5 | 403211140040131 |
6 | 15334103501505 |
7 | 1552611155261 |
oct | 274132114461 |
9 | 72164612785 |
10 | 25256565041 |
11 | a790744154 |
12 | 4a8a457895 |
13 | 24c6737156 |
14 | 13184917a1 |
15 | 9cc4a1a2b |
hex | 5e1689931 |
25256565041 has 2 divisors, whose sum is σ = 25256565042. Its totient is φ = 25256565040.
The previous prime is 25256565017. The next prime is 25256565053. The reversal of 25256565041 is 14056565252.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 19181142016 + 6075423025 = 138496^2 + 77945^2 .
It is a cyclic number.
It is not a de Polignac number, because 25256565041 - 214 = 25256548657 is a prime.
It is a super-3 number, since 3×252565650413 (a number of 32 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 25256565041.
It is not a weakly prime, because it can be changed into another prime (25256565001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12628282520 + 12628282521.
It is an arithmetic number, because the mean of its divisors is an integer number (12628282521).
Almost surely, 225256565041 is an apocalyptic number.
It is an amenable number.
25256565041 is a deficient number, since it is larger than the sum of its proper divisors (1).
25256565041 is an equidigital number, since it uses as much as digits as its factorization.
25256565041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 360000, while the sum is 41.
The spelling of 25256565041 in words is "twenty-five billion, two hundred fifty-six million, five hundred sixty-five thousand, forty-one".
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