Base | Representation |
---|---|
bin | 1011011111100110011101… |
… | …01101001101011001001001 |
3 | 10022111021100002002011102002 |
4 | 11233303032231031121021 |
5 | 11303101303203334442 |
6 | 125431111125120345 |
7 | 5216030303133656 |
oct | 557631655153111 |
9 | 108437302064362 |
10 | 25275055527497 |
11 | 80650aaa20466 |
12 | 2a02584b590b5 |
13 | 11145733126a9 |
14 | 635467cd4c2d |
15 | 2dc6dedb1732 |
hex | 16fcceb4d649 |
25275055527497 has 2 divisors, whose sum is σ = 25275055527498. Its totient is φ = 25275055527496.
The previous prime is 25275055527427. The next prime is 25275055527521. The reversal of 25275055527497 is 79472555057252.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15091834202041 + 10183221325456 = 3884821^2 + 3191116^2 .
It is a cyclic number.
It is not a de Polignac number, because 25275055527497 - 210 = 25275055526473 is a prime.
It is not a weakly prime, because it can be changed into another prime (25275055527427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12637527763748 + 12637527763749.
It is an arithmetic number, because the mean of its divisors is an integer number (12637527763749).
Almost surely, 225275055527497 is an apocalyptic number.
It is an amenable number.
25275055527497 is a deficient number, since it is larger than the sum of its proper divisors (1).
25275055527497 is an equidigital number, since it uses as much as digits as its factorization.
25275055527497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 308700000, while the sum is 65.
The spelling of 25275055527497 in words is "twenty-five trillion, two hundred seventy-five billion, fifty-five million, five hundred twenty-seven thousand, four hundred ninety-seven".
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