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252753774134401 is a prime number
BaseRepresentation
bin111001011110000011010010…
…111011000100010010000001
31020010221000200002122122010201
4321132003102323010102001
5231112104212134300101
62253321251511325201
7104144600101003411
oct7136032273042201
91203830602578121
10252753774134401
1173598301248a01
122442145b680801
13ab0576a332097
14465b4c2a70641
151e34a8bb35e01
hexe5e0d2ec4481

252753774134401 has 2 divisors, whose sum is σ = 252753774134402. Its totient is φ = 252753774134400.

The previous prime is 252753774134293. The next prime is 252753774134423. The reversal of 252753774134401 is 104431477357252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 252682847792001 + 70926342400 = 15896001^2 + 266320^2 .

It is a cyclic number.

It is not a de Polignac number, because 252753774134401 - 217 = 252753774003329 is a prime.

It is not a weakly prime, because it can be changed into another prime (252753774132401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126376887067200 + 126376887067201.

It is an arithmetic number, because the mean of its divisors is an integer number (126376887067201).

Almost surely, 2252753774134401 is an apocalyptic number.

It is an amenable number.

252753774134401 is a deficient number, since it is larger than the sum of its proper divisors (1).

252753774134401 is an equidigital number, since it uses as much as digits as its factorization.

252753774134401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19756800, while the sum is 55.

The spelling of 252753774134401 in words is "two hundred fifty-two trillion, seven hundred fifty-three billion, seven hundred seventy-four million, one hundred thirty-four thousand, four hundred one".