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252775013775 = 3523370333517
BaseRepresentation
bin1110101101101010010…
…0001001110110001111
3220011110022210011101020
43223122210021312033
513120140400420100
6312042341445223
724156000110634
oct3533244116617
9804408704336
10252775013775
11982239a6169
1240ba5a10813
131aab4c7b28b
14c33d1b018b
15689676a5a0
hex3ada909d8f

252775013775 has 12 divisors (see below), whose sum is σ = 417921356232. Its totient is φ = 134813340640.

The previous prime is 252775013749. The next prime is 252775013807. The reversal of 252775013775 is 577310577252.

It is not a de Polignac number, because 252775013775 - 29 = 252775013263 is a prime.

It is a super-3 number, since 3×2527750137753 (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1685166684 + ... + 1685166833.

It is an arithmetic number, because the mean of its divisors is an integer number (34826779686).

Almost surely, 2252775013775 is an apocalyptic number.

252775013775 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

252775013775 is a deficient number, since it is larger than the sum of its proper divisors (165146342457).

252775013775 is a wasteful number, since it uses less digits than its factorization.

252775013775 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3370333530 (or 3370333525 counting only the distinct ones).

The product of its (nonzero) digits is 3601500, while the sum is 51.

The spelling of 252775013775 in words is "two hundred fifty-two billion, seven hundred seventy-five million, thirteen thousand, seven hundred seventy-five".

Divisors: 1 3 5 15 25 75 3370333517 10111000551 16851667585 50555002755 84258337925 252775013775