Base | Representation |
---|---|
bin | 1110101101101011100… |
… | …1001100100101001001 |
3 | 220011110201011102012121 |
4 | 3223122321030211021 |
5 | 13120143303424433 |
6 | 312043100011241 |
7 | 24156065024125 |
oct | 3533271144511 |
9 | 804421142177 |
10 | 252780529993 |
11 | 98227023622 |
12 | 40ba7830b21 |
13 | 1aab6160004 |
14 | c33dc08585 |
15 | 6896ea9c2d |
hex | 3adae4c949 |
252780529993 has 2 divisors, whose sum is σ = 252780529994. Its totient is φ = 252780529992.
The previous prime is 252780529973. The next prime is 252780530027. The reversal of 252780529993 is 399925087252.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 176301733689 + 76478796304 = 419883^2 + 276548^2 .
It is a cyclic number.
It is not a de Polignac number, because 252780529993 - 225 = 252746975561 is a prime.
It is not a weakly prime, because it can be changed into another prime (252780529943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126390264996 + 126390264997.
It is an arithmetic number, because the mean of its divisors is an integer number (126390264997).
Almost surely, 2252780529993 is an apocalyptic number.
It is an amenable number.
252780529993 is a deficient number, since it is larger than the sum of its proper divisors (1).
252780529993 is an equidigital number, since it uses as much as digits as its factorization.
252780529993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24494400, while the sum is 61.
The spelling of 252780529993 in words is "two hundred fifty-two billion, seven hundred eighty million, five hundred twenty-nine thousand, nine hundred ninety-three".
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