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252911993 is a prime number
BaseRepresentation
bin11110001001100…
…10000101111001
3122121220021000212
433010302011321
51004221140433
641032440505
76160500515
oct1704620571
9577807025
10252911993
1111a842584
1270849135
1340521c89
1425837145
151730bd48
hexf132179

252911993 has 2 divisors, whose sum is σ = 252911994. Its totient is φ = 252911992.

The previous prime is 252911969. The next prime is 252912031. The reversal of 252911993 is 399119252.

252911993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 225840784 + 27071209 = 15028^2 + 5203^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-252911993 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 252911993.

It is not a weakly prime, because it can be changed into another prime (252911963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126455996 + 126455997.

It is an arithmetic number, because the mean of its divisors is an integer number (126455997).

Almost surely, 2252911993 is an apocalyptic number.

It is an amenable number.

252911993 is a deficient number, since it is larger than the sum of its proper divisors (1).

252911993 is an equidigital number, since it uses as much as digits as its factorization.

252911993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 43740, while the sum is 41.

The square root of 252911993 is about 15903.2070036204. The cubic root of 252911993 is about 632.3970101075.

The spelling of 252911993 in words is "two hundred fifty-two million, nine hundred eleven thousand, nine hundred ninety-three".