Base | Representation |
---|---|
bin | 100100110100110011100… |
… | …101001110011111010011 |
3 | 22221220220221111020110020 |
4 | 210310303211032133103 |
5 | 312430132342242120 |
6 | 5214313032434523 |
7 | 350554440504552 |
oct | 44646345163723 |
9 | 8856827436406 |
10 | 2530601134035 |
11 | 8962494051a7 |
12 | 34a545248a43 |
13 | 15483347c040 |
14 | 8a6a5cbbd99 |
15 | 45c603cd640 |
hex | 24d3394e7d3 |
2530601134035 has 32 divisors (see below), whose sum is σ = 4384511197248. Its totient is φ = 1238951324160.
The previous prime is 2530601133997. The next prime is 2530601134043. The reversal of 2530601134035 is 5304311060352.
It is not a de Polignac number, because 2530601134035 - 28 = 2530601133779 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2530601133987 and 2530601134005.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 35813992 + ... + 35884581.
It is an arithmetic number, because the mean of its divisors is an integer number (137015974914).
Almost surely, 22530601134035 is an apocalyptic number.
2530601134035 is a deficient number, since it is larger than the sum of its proper divisors (1853910063213).
2530601134035 is a wasteful number, since it uses less digits than its factorization.
2530601134035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71698775.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 2530601134035 its reverse (5304311060352), we get a palindrome (7834912194387).
The spelling of 2530601134035 in words is "two trillion, five hundred thirty billion, six hundred one million, one hundred thirty-four thousand, thirty-five".
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