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2530601133997 is a prime number
BaseRepresentation
bin100100110100110011100…
…101001110011110101101
322221220220221111020101211
4210310303211032132231
5312430132342241442
65214313032434421
7350554440504466
oct44646345163655
98856827436354
102530601133997
11896249405172
1234a545248a11
1315483347c011
148a6a5cbbd6d
1545c603cd617
hex24d3394e7ad

2530601133997 has 2 divisors, whose sum is σ = 2530601133998. Its totient is φ = 2530601133996.

The previous prime is 2530601133989. The next prime is 2530601134043. The reversal of 2530601133997 is 7993311060352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2530075165641 + 525968356 = 1590621^2 + 22934^2 .

It is a cyclic number.

It is not a de Polignac number, because 2530601133997 - 23 = 2530601133989 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2530601133997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2530601133947) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265300566998 + 1265300566999.

It is an arithmetic number, because the mean of its divisors is an integer number (1265300566999).

Almost surely, 22530601133997 is an apocalyptic number.

It is an amenable number.

2530601133997 is a deficient number, since it is larger than the sum of its proper divisors (1).

2530601133997 is an equidigital number, since it uses as much as digits as its factorization.

2530601133997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 918540, while the sum is 49.

The spelling of 2530601133997 in words is "two trillion, five hundred thirty billion, six hundred one million, one hundred thirty-three thousand, nine hundred ninety-seven".