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25313124232537 is a prime number
BaseRepresentation
bin1011100000101101010111…
…10001110010110101011001
310022121220121011001202021121
411300112223301302311121
511304212234300420122
6125500404433405241
75221545546604141
oct560265361626531
9108556534052247
1025313124232537
11807a265798a69
122a09a2a109821
13111802c224b6b
14637239bad921
152dd6bc057bc7
hex1705abc72d59

25313124232537 has 2 divisors, whose sum is σ = 25313124232538. Its totient is φ = 25313124232536.

The previous prime is 25313124232421. The next prime is 25313124232577. The reversal of 25313124232537 is 73523242131352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24458998924816 + 854125307721 = 4945604^2 + 924189^2 .

It is a cyclic number.

It is not a de Polignac number, because 25313124232537 - 223 = 25313115843929 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25313124232493 and 25313124232502.

It is not a weakly prime, because it can be changed into another prime (25313124232577) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12656562116268 + 12656562116269.

It is an arithmetic number, because the mean of its divisors is an integer number (12656562116269).

Almost surely, 225313124232537 is an apocalyptic number.

It is an amenable number.

25313124232537 is a deficient number, since it is larger than the sum of its proper divisors (1).

25313124232537 is an equidigital number, since it uses as much as digits as its factorization.

25313124232537 is an evil number, because the sum of its binary digits is even.

The product of its digits is 907200, while the sum is 43.

Adding to 25313124232537 its reverse (73523242131352), we get a palindrome (98836366363889).

The spelling of 25313124232537 in words is "twenty-five trillion, three hundred thirteen billion, one hundred twenty-four million, two hundred thirty-two thousand, five hundred thirty-seven".