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2531475105121 is a prime number
BaseRepresentation
bin100100110101100111101…
…011001010010101100001
322222000011212000120101201
4210311213223022111201
5312433430111330441
65214535453001201
7350615212234324
oct44654753122541
98860155016351
102531475105121
11896657779656
1234a749a83201
131549425610b1
148a749dc07bb
1545cb1eb7c31
hex24d67aca561

2531475105121 has 2 divisors, whose sum is σ = 2531475105122. Its totient is φ = 2531475105120.

The previous prime is 2531475105011. The next prime is 2531475105179. The reversal of 2531475105121 is 1215015741352.

2531475105121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1489669070400 + 1041806034721 = 1220520^2 + 1020689^2 .

It is a cyclic number.

It is not a de Polignac number, because 2531475105121 - 27 = 2531475104993 is a prime.

It is not a weakly prime, because it can be changed into another prime (2531475105221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265737552560 + 1265737552561.

It is an arithmetic number, because the mean of its divisors is an integer number (1265737552561).

Almost surely, 22531475105121 is an apocalyptic number.

It is an amenable number.

2531475105121 is a deficient number, since it is larger than the sum of its proper divisors (1).

2531475105121 is an equidigital number, since it uses as much as digits as its factorization.

2531475105121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 42000, while the sum is 37.

The spelling of 2531475105121 in words is "two trillion, five hundred thirty-one billion, four hundred seventy-five million, one hundred five thousand, one hundred twenty-one".