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2532074147 is a prime number
BaseRepresentation
bin1001011011101100…
…0110001010100011
320112110112200201222
42112323012022203
520141202333042
61055131045255
7116514163241
oct22673061243
96473480658
102532074147
11108a320869
125a7ba082b
1331477c535
141a03dd791
15ec4642d2
hex96ec62a3

2532074147 has 2 divisors, whose sum is σ = 2532074148. Its totient is φ = 2532074146.

The previous prime is 2532074123. The next prime is 2532074161. The reversal of 2532074147 is 7414702352.

2532074147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2532074147 - 210 = 2532073123 is a prime.

It is a super-3 number, since 3×25320741473 (a number of 29 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (2532074107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1266037073 + 1266037074.

It is an arithmetic number, because the mean of its divisors is an integer number (1266037074).

Almost surely, 22532074147 is an apocalyptic number.

2532074147 is a deficient number, since it is larger than the sum of its proper divisors (1).

2532074147 is an equidigital number, since it uses as much as digits as its factorization.

2532074147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 47040, while the sum is 35.

The square root of 2532074147 is about 50319.7192659101. The cubic root of 2532074147 is about 1362.9883371657.

Adding to 2532074147 its reverse (7414702352), we get a palindrome (9946776499).

The spelling of 2532074147 in words is "two billion, five hundred thirty-two million, seventy-four thousand, one hundred forty-seven".