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25325521433 is a prime number
BaseRepresentation
bin10111100101100001…
…001100101000011001
32102100222102210021022
4113211201030220121
5403331313141213
615345005452225
71554406244312
oct274541145031
972328383238
1025325521433
11a816662103
124aa9571075
132507acb954
1413236c1609
159d3573308
hex5e584ca19

25325521433 has 2 divisors, whose sum is σ = 25325521434. Its totient is φ = 25325521432.

The previous prime is 25325521427. The next prime is 25325521471. The reversal of 25325521433 is 33412552352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24980750809 + 344770624 = 158053^2 + 18568^2 .

It is a cyclic number.

It is not a de Polignac number, because 25325521433 - 26 = 25325521369 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 25325521393 and 25325521402.

It is not a weakly prime, because it can be changed into another prime (25325511433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12662760716 + 12662760717.

It is an arithmetic number, because the mean of its divisors is an integer number (12662760717).

Almost surely, 225325521433 is an apocalyptic number.

It is an amenable number.

25325521433 is a deficient number, since it is larger than the sum of its proper divisors (1).

25325521433 is an equidigital number, since it uses as much as digits as its factorization.

25325521433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 108000, while the sum is 35.

The spelling of 25325521433 in words is "twenty-five billion, three hundred twenty-five million, five hundred twenty-one thousand, four hundred thirty-three".