Base | Representation |
---|---|
bin | 1110101111101001111… |
… | …0110101111101010001 |
3 | 220012211122101022002111 |
4 | 3223322132311331101 |
5 | 13122234441224442 |
6 | 312211430545321 |
7 | 24205161442246 |
oct | 3537236657521 |
9 | 805748338074 |
10 | 253310492497 |
11 | 98479195267 |
12 | 41115208241 |
13 | 1ab6bba5caa |
14 | c39035d5cd |
15 | 68c8790b17 |
hex | 3afa7b5f51 |
253310492497 has 2 divisors, whose sum is σ = 253310492498. Its totient is φ = 253310492496.
The previous prime is 253310492483. The next prime is 253310492503. The reversal of 253310492497 is 794294013352.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 145978249041 + 107332243456 = 382071^2 + 327616^2 .
It is a cyclic number.
It is not a de Polignac number, because 253310492497 - 211 = 253310490449 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 253310492497.
It is not a weakly prime, because it can be changed into another prime (253310492437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126655246248 + 126655246249.
It is an arithmetic number, because the mean of its divisors is an integer number (126655246249).
Almost surely, 2253310492497 is an apocalyptic number.
It is an amenable number.
253310492497 is a deficient number, since it is larger than the sum of its proper divisors (1).
253310492497 is an equidigital number, since it uses as much as digits as its factorization.
253310492497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1632960, while the sum is 49.
The spelling of 253310492497 in words is "two hundred fifty-three billion, three hundred ten million, four hundred ninety-two thousand, four hundred ninety-seven".
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