253412413112135 has 4 divisors (see below), whose sum is σ = 304094895734568. Its totient is φ = 202729930489704.

The previous prime is 253412413112087. The next prime is 253412413112197. The reversal of 253412413112135 is 531211314214352.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 253412413112135 - 2¹⁸ = 253412412849991 is a prime.

It is a super-3 number, since 3×253412413112135³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25341241311209 + ... + 25341241311218.

It is an arithmetic number, because the mean of its divisors is an integer number (76023723933642).

Almost surely, 2^{253412413112135} is an apocalyptic number.

253412413112135 is a deficient number, since it is larger than the sum of its proper divisors (50682482622433).

253412413112135 is an equidigital number, since it uses as much as digits as its factorization.

253412413112135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50682482622432.

The product of its digits is 86400, while the sum is 38.

Adding to 253412413112135 its reverse (531211314214352), we get a palindrome (784623727326487).

The spelling of 253412413112135 in words is "two hundred fifty-three trillion, four hundred twelve billion, four hundred thirteen million, one hundred twelve thousand, one hundred thirty-five".