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253412521510399 = 4717231312910207
BaseRepresentation
bin111001100111101000110011…
…010100111000010111111111
31020020021000000100001121021121
4321213220303110320113333
5231203402321001313044
62254544034422011411
7104243310343214206
oct7147506324702777
91206230010047247
10253412521510399
1173821712a3a609
1224509064876b67
13ab5291005b724
14468133529a23d
151e46c94273984
hexe67a335385ff

253412521510399 has 8 divisors (see below), whose sum is σ = 258819297804288. Its totient is φ = 248006371071480.

The previous prime is 253412521510373. The next prime is 253412521510483. The reversal of 253412521510399 is 993015125214352.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 253412521510399 - 213 = 253412521502207 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253412521510349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 155645247 + ... + 157264960.

It is an arithmetic number, because the mean of its divisors is an integer number (32352412225536).

Almost surely, 2253412521510399 is an apocalyptic number.

253412521510399 is a deficient number, since it is larger than the sum of its proper divisors (5406776293889).

253412521510399 is a wasteful number, since it uses less digits than its factorization.

253412521510399 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312927485.

The product of its (nonzero) digits is 2916000, while the sum is 52.

The spelling of 253412521510399 in words is "two hundred fifty-three trillion, four hundred twelve billion, five hundred twenty-one million, five hundred ten thousand, three hundred ninety-nine".

Divisors: 1 47 17231 809857 312910207 14706779729 5391755776817 253412521510399