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253420003000457 is a prime number
BaseRepresentation
bin111001100111101111110001…
…010000100000000010001001
31020020021201022201210200020222
4321213233301100200002021
5231204013131232003312
62254551313040155425
7104243663626635446
oct7147576120400211
91206251281720228
10253420003000457
1173824902058847
122450a5b2308b75
13ab53533038617
144681844b509cd
151e47080e9b672
hexe67bf1420089

253420003000457 has 2 divisors, whose sum is σ = 253420003000458. Its totient is φ = 253420003000456.

The previous prime is 253420003000387. The next prime is 253420003000487. The reversal of 253420003000457 is 754000300024352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129053144344336 + 124366858656121 = 11360156^2 + 11151989^2 .

It is a cyclic number.

It is not a de Polignac number, because 253420003000457 - 212 = 253420002996361 is a prime.

It is not a weakly prime, because it can be changed into another prime (253420003000487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126710001500228 + 126710001500229.

It is an arithmetic number, because the mean of its divisors is an integer number (126710001500229).

Almost surely, 2253420003000457 is an apocalyptic number.

It is an amenable number.

253420003000457 is a deficient number, since it is larger than the sum of its proper divisors (1).

253420003000457 is an equidigital number, since it uses as much as digits as its factorization.

253420003000457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 100800, while the sum is 35.

The spelling of 253420003000457 in words is "two hundred fifty-three trillion, four hundred twenty billion, three million, four hundred fifty-seven", and thus it is an aban number.