Base | Representation |
---|---|
bin | 111001100111111001011001… |
… | …100001011111100010101011 |
3 | 1020020022201000021212110001011 |
4 | 321213321121201133202223 |
5 | 231204200320102014242 |
6 | 2255000143021404351 |
7 | 104244511063564504 |
oct | 7147713141374253 |
9 | 1206281007773034 |
10 | 253430342219947 |
11 | 738292282a4442 |
12 | 245105b8a096b7 |
13 | ab544c00a6089 |
14 | 4682145d75bab |
15 | 1e47488a13d17 |
hex | e67e5985f8ab |
253430342219947 has 2 divisors, whose sum is σ = 253430342219948. Its totient is φ = 253430342219946.
The previous prime is 253430342219921. The next prime is 253430342220101. The reversal of 253430342219947 is 749912243034352.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 253430342219947 - 219 = 253430341695659 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 253430342219891 and 253430342219900.
It is not a weakly prime, because it can be changed into another prime (253430342213947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126715171109973 + 126715171109974.
It is an arithmetic number, because the mean of its divisors is an integer number (126715171109974).
Almost surely, 2253430342219947 is an apocalyptic number.
253430342219947 is a deficient number, since it is larger than the sum of its proper divisors (1).
253430342219947 is an equidigital number, since it uses as much as digits as its factorization.
253430342219947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39191040, while the sum is 58.
The spelling of 253430342219947 in words is "two hundred fifty-three trillion, four hundred thirty billion, three hundred forty-two million, two hundred nineteen thousand, nine hundred forty-seven".
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