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253430342219947 is a prime number
BaseRepresentation
bin111001100111111001011001…
…100001011111100010101011
31020020022201000021212110001011
4321213321121201133202223
5231204200320102014242
62255000143021404351
7104244511063564504
oct7147713141374253
91206281007773034
10253430342219947
11738292282a4442
12245105b8a096b7
13ab544c00a6089
144682145d75bab
151e47488a13d17
hexe67e5985f8ab

253430342219947 has 2 divisors, whose sum is σ = 253430342219948. Its totient is φ = 253430342219946.

The previous prime is 253430342219921. The next prime is 253430342220101. The reversal of 253430342219947 is 749912243034352.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 253430342219947 - 219 = 253430341695659 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 253430342219891 and 253430342219900.

It is not a weakly prime, because it can be changed into another prime (253430342213947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126715171109973 + 126715171109974.

It is an arithmetic number, because the mean of its divisors is an integer number (126715171109974).

Almost surely, 2253430342219947 is an apocalyptic number.

253430342219947 is a deficient number, since it is larger than the sum of its proper divisors (1).

253430342219947 is an equidigital number, since it uses as much as digits as its factorization.

253430342219947 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 39191040, while the sum is 58.

The spelling of 253430342219947 in words is "two hundred fifty-three trillion, four hundred thirty billion, three hundred forty-two million, two hundred nineteen thousand, nine hundred forty-seven".