Base | Representation |
---|---|
bin | 111001100111111010010101… |
… | …001011101011011001110011 |
3 | 1020020022210121001021011102222 |
4 | 321213322111023223121303 |
5 | 231204204342320244243 |
6 | 2255000430214431255 |
7 | 104244544636324304 |
oct | 7147722513533163 |
9 | 1206283531234388 |
10 | 253431343134323 |
11 | 738296a1292202 |
12 | 2451083806252b |
13 | ab5461c5734c3 |
14 | 46821dcc807ab |
15 | 1e474e6826168 |
hex | e67e952eb673 |
253431343134323 has 2 divisors, whose sum is σ = 253431343134324. Its totient is φ = 253431343134322.
The previous prime is 253431343134317. The next prime is 253431343134353. The reversal of 253431343134323 is 323431343134352.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 253431343134323 - 210 = 253431343133299 is a prime.
It is not a weakly prime, because it can be changed into another prime (253431343134353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126715671567161 + 126715671567162.
It is an arithmetic number, because the mean of its divisors is an integer number (126715671567162).
Almost surely, 2253431343134323 is an apocalyptic number.
253431343134323 is a deficient number, since it is larger than the sum of its proper divisors (1).
253431343134323 is an equidigital number, since it uses as much as digits as its factorization.
253431343134323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2799360, while the sum is 44.
Adding to 253431343134323 its reverse (323431343134352), we get a palindrome (576862686268675).
The spelling of 253431343134323 in words is "two hundred fifty-three trillion, four hundred thirty-one billion, three hundred forty-three million, one hundred thirty-four thousand, three hundred twenty-three".
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