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253431503214400 = 26527171331047811
BaseRepresentation
bin111001100111111010011110…
…101110010101011101000000
31020020022211000012111002000201
4321213322132232111131000
5231204210204310330100
62255000454133454544
7104244551622066130
oct7147723656253500
91206284005432021
10253431503214400
1173829773689795
12245108817a1454
13ab54646791544
144682216230ac0
151e475058e736a
hexe67e9eb95740

253431503214400 has 168 divisors, whose sum is σ = 754608273961536. Its totient is φ = 81779577446400.

The previous prime is 253431503214371. The next prime is 253431503214433. The reversal of 253431503214400 is 4412305134352.

It is a self number, because there is not a number n which added to its sum of digits gives 253431503214400.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 665333506 + ... + 665714305.

Almost surely, 2253431503214400 is an apocalyptic number.

253431503214400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

253431503214400 is an abundant number, since it is smaller than the sum of its proper divisors (501176770747136).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

253431503214400 is a wasteful number, since it uses less digits than its factorization.

253431503214400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1331047857 (or 1331047842 counting only the distinct ones).

The product of its (nonzero) digits is 172800, while the sum is 37.

Adding to 253431503214400 its reverse (4412305134352), we get a palindrome (257843808348752).

The spelling of 253431503214400 in words is "two hundred fifty-three trillion, four hundred thirty-one billion, five hundred three million, two hundred fourteen thousand, four hundred".