Base | Representation |
---|---|
bin | 1011100001100101011001… |
… | …01011001110101111010001 |
3 | 10022201210020110120022111121 |
4 | 11300302230223032233101 |
5 | 11310210340214410423 |
6 | 125522301320442241 |
7 | 5223662136120352 |
oct | 560625453165721 |
9 | 108653213508447 |
10 | 25343204060113 |
11 | 8090aa0aa56a5 |
12 | 2a13823919381 |
13 | 111ab13cb99c4 |
14 | 638890a77d29 |
15 | 2de37cb9e45d |
hex | 170cacacebd1 |
25343204060113 has 4 divisors (see below), whose sum is σ = 25349684044608. Its totient is φ = 25336724075620.
The previous prime is 25343204060029. The next prime is 25343204060147. The reversal of 25343204060113 is 31106040234352.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 25343204060113 - 229 = 25342667189201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25343204060183) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3239986381 + ... + 3239994202.
It is an arithmetic number, because the mean of its divisors is an integer number (6337421011152).
Almost surely, 225343204060113 is an apocalyptic number.
It is an amenable number.
25343204060113 is a deficient number, since it is larger than the sum of its proper divisors (6479984495).
25343204060113 is an equidigital number, since it uses as much as digits as its factorization.
25343204060113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6479984494.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 25343204060113 its reverse (31106040234352), we get a palindrome (56449244294465).
The spelling of 25343204060113 in words is "twenty-five trillion, three hundred forty-three billion, two hundred four million, sixty thousand, one hundred thirteen".
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