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253625998033 is a prime number
BaseRepresentation
bin1110110000110101001…
…0011001101011010001
3220020122122001122022201
43230031102121223101
513123411223414113
6312303021203201
724216042261412
oct3541522315321
9806578048281
10253625998033
119862029a241
12411a2a00501
131abbc372565
14c3c020b809
1568e6313cdd
hex3b0d499ad1

253625998033 has 2 divisors, whose sum is σ = 253625998034. Its totient is φ = 253625998032.

The previous prime is 253625997997. The next prime is 253625998037. The reversal of 253625998033 is 330899526352.

253625998033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 175453752384 + 78172245649 = 418872^2 + 279593^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-253625998033 is a prime.

It is a super-2 number, since 2×2536259980332 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (253625998037) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126812999016 + 126812999017.

It is an arithmetic number, because the mean of its divisors is an integer number (126812999017).

Almost surely, 2253625998033 is an apocalyptic number.

It is an amenable number.

253625998033 is a deficient number, since it is larger than the sum of its proper divisors (1).

253625998033 is an equidigital number, since it uses as much as digits as its factorization.

253625998033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10497600, while the sum is 55.

The spelling of 253625998033 in words is "two hundred fifty-three billion, six hundred twenty-five million, nine hundred ninety-eight thousand, thirty-three".