25373540538667 has 4 divisors (see below), whose sum is σ = 25373603971840. Its totient is φ = 25373477105496.

The previous prime is 25373540538653. The next prime is 25373540538677. The reversal of 25373540538667 is 76683504537352.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 25373540538667 - 2³⁵ = 25339180800299 is a prime.

It is a super-3 number, since 3×25373540538667³ (a number of 41 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 25373540538599 and 25373540538608.

It is not an unprimeable number, because it can be changed into a prime (25373540538677) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31112748 + ... + 31917865.

It is an arithmetic number, because the mean of its divisors is an integer number (6343400992960).

Almost surely, 2^{25373540538667} is an apocalyptic number.

25373540538667 is a deficient number, since it is larger than the sum of its proper divisors (63433173).

25373540538667 is an equidigital number, since it uses as much as digits as its factorization.

25373540538667 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63433172.

The product of its (nonzero) digits is 381024000, while the sum is 64.

The spelling of 25373540538667 in words is "twenty-five trillion, three hundred seventy-three billion, five hundred forty million, five hundred thirty-eight thousand, six hundred sixty-seven".