25388509963 has 2 divisors, whose sum is σ = 25388509964. Its totient is φ = 25388509962.

The previous prime is 25388509943. The next prime is 25388510009. The reversal of 25388509963 is 36990588352.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 25388509963 - 2¹³ = 25388501771 is a prime.

It is a super-2 number, since 2×25388509963² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25388509898 and 25388509907.

It is not a weakly prime, because it can be changed into another prime (25388509933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12694254981 + 12694254982.

It is an arithmetic number, because the mean of its divisors is an integer number (12694254982).

Almost surely, 2^25388509963 is an apocalyptic number.

25388509963 is a deficient number, since it is larger than the sum of its proper divisors (1).

25388509963 is an equidigital number, since it uses as much as digits as its factorization.

25388509963 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13996800, while the sum is 58.

The spelling of 25388509963 in words is "twenty-five billion, three hundred eighty-eight million, five hundred nine thousand, nine hundred sixty-three".