Base | Representation |
---|---|
bin | 1110110010000111000… |
… | …1001010011100010001 |
3 | 220021112120121202102011 |
4 | 3230201301022130101 |
5 | 13130112204401132 |
6 | 312401054022521 |
7 | 24230414015212 |
oct | 3544161123421 |
9 | 807476552364 |
10 | 253969606417 |
11 | 9878724930a |
12 | 41279aa7a41 |
13 | 1ac455cb427 |
14 | c413ad3409 |
15 | 6916588b47 |
hex | 3b21c4a711 |
253969606417 has 2 divisors, whose sum is σ = 253969606418. Its totient is φ = 253969606416.
The previous prime is 253969606379. The next prime is 253969606427. The reversal of 253969606417 is 714606969352.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 193431956481 + 60537649936 = 439809^2 + 246044^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-253969606417 is a prime.
It is not a weakly prime, because it can be changed into another prime (253969606427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126984803208 + 126984803209.
It is an arithmetic number, because the mean of its divisors is an integer number (126984803209).
Almost surely, 2253969606417 is an apocalyptic number.
It is an amenable number.
253969606417 is a deficient number, since it is larger than the sum of its proper divisors (1).
253969606417 is an equidigital number, since it uses as much as digits as its factorization.
253969606417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14696640, while the sum is 58.
The spelling of 253969606417 in words is "two hundred fifty-three billion, nine hundred sixty-nine million, six hundred six thousand, four hundred seventeen".
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