2539713947904 has 1701 divisors, whose sum is σ = 9705178819161. Its totient is φ = 660917698560.

The previous prime is 2539713947891. The next prime is 2539713947933. The reversal of 2539713947904 is 4097493179352.

The square root of 2539713947904 is 1593648.

It is a perfect power (a square), and thus also a powerful number.

2539713947904 is a `hidden beast` number, since 2 + 539 + 7 + 1 + 3 + 9 + 4 + 7 + 90 + 4 = 666.

It can be written as a sum of positive squares in only one way, i.e., 1977285945600 + 562428002304 = 1406160^2 + 749952^2 .

It is a tau number, because it is divible by the number of its divisors (1701).

It is a Harshad number since it is a multiple of its sum of digits (63).

It is an unprimeable number.

It is a polite number, since it can be written in 188 ways as a sum of consecutive naturals, for example, 81926256369 + ... + 81926256399.

Almost surely, 2^{2539713947904} is an apocalyptic number.

2539713947904 is a gapful number since it is divisible by the number (24) formed by its first and last digit.

2539713947904 is the 1593648-th square number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2539713947904

2539713947904 is an abundant number, since it is smaller than the sum of its proper divisors (7165464871257).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2539713947904 is an frugal number, since it uses more digits than its factorization.

2539713947904 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144 (or 60 counting only the distinct ones).

The product of its (nonzero) digits is 51438240, while the sum is 63.

The spelling of 2539713947904 in words is "two trillion, five hundred thirty-nine billion, seven hundred thirteen million, nine hundred forty-seven thousand, nine hundred four".