Base | Representation |
---|---|
bin | 110000011100… |
… | …1001011000011 |
3 | 1202210110020212 |
4 | 1200321023003 |
5 | 23000300003 |
6 | 2304224335 |
7 | 425616326 |
oct | 140711303 |
9 | 52713225 |
10 | 25400003 |
11 | 13379442 |
12 | 860b0ab |
13 | 53542b5 |
14 | 35327bd |
15 | 236add8 |
hex | 18392c3 |
25400003 has 2 divisors, whose sum is σ = 25400004. Its totient is φ = 25400002.
The previous prime is 25399987. The next prime is 25400009. The reversal of 25400003 is 30000452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25400003 - 24 = 25399987 is a prime.
It is not a weakly prime, because it can be changed into another prime (25400009) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12700001 + 12700002.
It is an arithmetic number, because the mean of its divisors is an integer number (12700002).
Almost surely, 225400003 is an apocalyptic number.
25400003 is a deficient number, since it is larger than the sum of its proper divisors (1).
25400003 is an equidigital number, since it uses as much as digits as its factorization.
25400003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 14.
The square root of 25400003 is about 5039.8415649701. The cubic root of 25400003 is about 293.9530174665.
Adding to 25400003 its reverse (30000452), we get a palindrome (55400455).
The spelling of 25400003 in words is "twenty-five million, four hundred thousand, three".
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