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25401772254137 is a prime number
BaseRepresentation
bin1011100011010010011111…
…00111001010001110111001
310022221101102011221211200212
411301221033213022032321
511312140312144113022
6130005225120240505
75231134411422536
oct561511747121671
9108841364854625
1025401772254137
11810391623a734
122a2304a170135
1311234b8c10406
1463b6492d9d8d
152e0b598783e2
hex171a4f9ca3b9

25401772254137 has 2 divisors, whose sum is σ = 25401772254138. Its totient is φ = 25401772254136.

The previous prime is 25401772254113. The next prime is 25401772254193. The reversal of 25401772254137 is 73145227710452.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19963193784361 + 5438578469776 = 4468019^2 + 2332076^2 .

It is a cyclic number.

It is not a de Polignac number, because 25401772254137 - 28 = 25401772253881 is a prime.

It is a super-2 number, since 2×254017722541372 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (25401772254437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12700886127068 + 12700886127069.

It is an arithmetic number, because the mean of its divisors is an integer number (12700886127069).

Almost surely, 225401772254137 is an apocalyptic number.

It is an amenable number.

25401772254137 is a deficient number, since it is larger than the sum of its proper divisors (1).

25401772254137 is an equidigital number, since it uses as much as digits as its factorization.

25401772254137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3292800, while the sum is 50.

Adding to 25401772254137 its reverse (73145227710452), we get a palindrome (98546999964589).

The spelling of 25401772254137 in words is "twenty-five trillion, four hundred one billion, seven hundred seventy-two million, two hundred fifty-four thousand, one hundred thirty-seven".