Base | Representation |
---|---|
bin | 100100111101110010001… |
… | …100011011100011001110 |
3 | 22222211210210121020212201 |
4 | 210331302030123203032 |
5 | 313104403313030014 |
6 | 5222545411552114 |
7 | 351345360524434 |
oct | 44756214334316 |
9 | 8884723536781 |
10 | 2540241533134 |
11 | 89a346137788 |
12 | 3503958bb63a |
13 | 15570b8012c6 |
14 | 8ad3c394d54 |
15 | 46126907e74 |
hex | 24f7231b8ce |
2540241533134 has 4 divisors (see below), whose sum is σ = 3810362299704. Its totient is φ = 1270120766566.
The previous prime is 2540241533131. The next prime is 2540241533161. The reversal of 2540241533134 is 4313351420452.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 2540241533093 and 2540241533102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2540241533131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 635060383282 + ... + 635060383285.
It is an arithmetic number, because the mean of its divisors is an integer number (952590574926).
Almost surely, 22540241533134 is an apocalyptic number.
2540241533134 is a deficient number, since it is larger than the sum of its proper divisors (1270120766570).
2540241533134 is a wasteful number, since it uses less digits than its factorization.
2540241533134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1270120766569.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 2540241533134 its reverse (4313351420452), we get a palindrome (6853592953586).
The spelling of 2540241533134 in words is "two trillion, five hundred forty billion, two hundred forty-one million, five hundred thirty-three thousand, one hundred thirty-four".
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