254031497 has 2 divisors, whose sum is σ = 254031498. Its totient is φ = 254031496.

The previous prime is 254031473. The next prime is 254031517. The reversal of 254031497 is 794130452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 151191616 + 102839881 = 12296^2 + 10141^2 .

It is a cyclic number.

It is not a de Polignac number, because 254031497 - 2⁶ = 254031433 is a prime.

It is a super-2 number, since 2×254031497² = 129064002936122018, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (254031467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127015748 + 127015749.

It is an arithmetic number, because the mean of its divisors is an integer number (127015749).

Almost surely, 2^254031497 is an apocalyptic number.

It is an amenable number.

254031497 is a deficient number, since it is larger than the sum of its proper divisors (1).

254031497 is an equidigital number, since it uses as much as digits as its factorization.

254031497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30240, while the sum is 35.

The square root of 254031497 is about 15938.3655686523. The cubic root of 254031497 is about 633.3287293910.

The spelling of 254031497 in words is "two hundred fifty-four million, thirty-one thousand, four hundred ninety-seven".