Base | Representation |
---|---|
bin | 10111101010001100… |
… | …101100100001110101 |
3 | 2102120110011121002100 |
4 | 113222030230201311 |
5 | 404011413030031 |
6 | 15400452332313 |
7 | 1556351501364 |
oct | 275214544165 |
9 | 72513147070 |
10 | 25404033141 |
11 | a856a07113 |
12 | 4b0b914099 |
13 | 251b15a796 |
14 | 132dcbb7db |
15 | 9da3d0de6 |
hex | 5ea32c875 |
25404033141 has 6 divisors (see below), whose sum is σ = 36694714550. Its totient is φ = 16936022088.
The previous prime is 25404033133. The next prime is 25404033143. The reversal of 25404033141 is 14133040452.
It is a happy number.
25404033141 is a `hidden beast` number, since 254 + 0 + 40 + 331 + 41 = 666.
It can be written as a sum of positive squares in only one way, i.e., 16695224100 + 8708809041 = 129210^2 + 93321^2 .
It is not a de Polignac number, because 25404033141 - 23 = 25404033133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25404033143) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1411335166 + ... + 1411335183.
Almost surely, 225404033141 is an apocalyptic number.
It is an amenable number.
25404033141 is a deficient number, since it is larger than the sum of its proper divisors (11290681409).
25404033141 is a wasteful number, since it uses less digits than its factorization.
25404033141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2822670355 (or 2822670352 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 27.
Adding to 25404033141 its reverse (14133040452), we get a palindrome (39537073593).
The spelling of 25404033141 in words is "twenty-five billion, four hundred four million, thirty-three thousand, one hundred forty-one".
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