Base | Representation |
---|---|
bin | 1011100011010111011101… |
… | …10011010010111111111001 |
3 | 10022221122022022110110020222 |
4 | 11301223232303102333321 |
5 | 11312211244402404423 |
6 | 130010350124025425 |
7 | 5231260531461053 |
oct | 561535663227771 |
9 | 108848268413228 |
10 | 25404443013113 |
11 | 8104a6687445a |
12 | 2a23674692275 |
13 | 1123823329478 |
14 | 63b81dcba8d3 |
15 | 2e0c640843c8 |
hex | 171aeecd2ff9 |
25404443013113 has 2 divisors, whose sum is σ = 25404443013114. Its totient is φ = 25404443013112.
The previous prime is 25404443013101. The next prime is 25404443013181. The reversal of 25404443013113 is 31131034440452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24488523193744 + 915919819369 = 4948588^2 + 957037^2 .
It is a cyclic number.
It is not a de Polignac number, because 25404443013113 - 220 = 25404441964537 is a prime.
It is not a weakly prime, because it can be changed into another prime (25404443013613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12702221506556 + 12702221506557.
It is an arithmetic number, because the mean of its divisors is an integer number (12702221506557).
Almost surely, 225404443013113 is an apocalyptic number.
It is an amenable number.
25404443013113 is a deficient number, since it is larger than the sum of its proper divisors (1).
25404443013113 is an equidigital number, since it uses as much as digits as its factorization.
25404443013113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 25404443013113 its reverse (31131034440452), we get a palindrome (56535477453565).
The spelling of 25404443013113 in words is "twenty-five trillion, four hundred four billion, four hundred forty-three million, thirteen thousand, one hundred thirteen".
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