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2540481179447 = 3932416460367
BaseRepresentation
bin100100111110000000011…
…110100110111100110111
322222212102111112112211002
4210332000132212330313
5313110401140220242
65223025252233515
7351354330504641
oct44760036467467
98885374475732
102540481179447
1189a459439592
1235044200b89b
1315574935a163
148ad62137891
154613c994432
hex24f807a6f37

2540481179447 has 4 divisors (see below), whose sum is σ = 2540488033056. Its totient is φ = 2540474325840.

The previous prime is 2540481179437. The next prime is 2540481179461. The reversal of 2540481179447 is 7449711840452.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2540481179447 - 28 = 2540481179191 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2540481179392 and 2540481179401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2540481179437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2836943 + ... + 3623424.

It is an arithmetic number, because the mean of its divisors is an integer number (635122008264).

Almost surely, 22540481179447 is an apocalyptic number.

2540481179447 is a deficient number, since it is larger than the sum of its proper divisors (6853609).

2540481179447 is an equidigital number, since it uses as much as digits as its factorization.

2540481179447 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6853608.

The product of its (nonzero) digits is 9031680, while the sum is 56.

The spelling of 2540481179447 in words is "two trillion, five hundred forty billion, four hundred eighty-one million, one hundred seventy-nine thousand, four hundred forty-seven".

Divisors: 1 393241 6460367 2540481179447