25405002614851 has 2 divisors, whose sum is σ = 25405002614852. Its totient is φ = 25405002614850.

The previous prime is 25405002614837. The next prime is 25405002614903. The reversal of 25405002614851 is 15841620050452.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 25405002614851 - 2³⁹ = 24855246800963 is a prime.

It is a super-2 number, since 2×25405002614851² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25405002614798 and 25405002614807.

It is not a weakly prime, because it can be changed into another prime (25405002614821) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12702501307425 + 12702501307426.

It is an arithmetic number, because the mean of its divisors is an integer number (12702501307426).

Almost surely, 2^{25405002614851} is an apocalyptic number.

25405002614851 is a deficient number, since it is larger than the sum of its proper divisors (1).

25405002614851 is an equidigital number, since it uses as much as digits as its factorization.

25405002614851 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384000, while the sum is 43.

The spelling of 25405002614851 in words is "twenty-five trillion, four hundred five billion, two million, six hundred fourteen thousand, eight hundred fifty-one".